q=%28%E6%B3%95%29%E5%A4%A7%E4%BB%B2%E9%A9%AC%28Alexandre+Dumas%29%E8%91%97%EF%BC%9B%E9%87%91%E5%AD%A9%E8%AF%91&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
(法)大仲马(Alexandre Dumas)著；金孩译